Question

Velocity is given by $v=4t(1-2t)$ then find time at which velocity is maximum.

• A. 0.5 sec
• B. 0.25 sec
• C. 0.45 sec
• D. 1 sec

Answer 1

Answer: (B)

$v=4t\left(1-2t\right)$
$\Rightarrow v=4t-8t^2$
For maximum velocity
$\frac{dv}{dt}0416t=0$
$\Rightarrow t=\frac{4}{16}=0.25s$