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Physics
Velocity is given by v = 4t(1 - 2t) then find time at which velocity is maximum.
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Q. Velocity is given by $v = 4t(1 - 2t)$ then find time at which velocity is maximum.
JIPMER
JIPMER 2018
Motion in a Straight Line
A
0.5 sec
11%
B
0.25 sec
66%
C
0.45 sec
7%
D
1 sec
16%
Solution:
$v=4t\left(1-2t\right)$
$\Rightarrow \quad v=4t-8t^{2}$
For maximum velocity
$\frac{dv}{dt}\quad0\quad4\quad16t=0$
$\Rightarrow \quad t=\frac{4}{16}=0.25\,s$