Question

Velocity constant of a reaction at $290K$ was found to be $3.2\times 10^{-3}$. At $300K$ it will be

• A. $1.28\times 10^{-2}$
• B. $9.6\times 10^{-3}$
• C. $6.4\times 10^{-3}$
• D. $3.2\times 10^{-4}$

Answer 1

Answer: (C)

As we know that the velocity constant become double by increasing the temperature by $10^{\circ }C$ so if at $290K$.
Velocity constant $=3.2\times 10^{-3}$ then at $300K$ velocity constant
$=2\left(K_{290}\right)=2\times 3.2\times$
$10^{-3}=6.4\times 10^{-3}$.