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Physics
Vectors a hati+b hatj+ hatk and 2 hati-3 hatj+4 hatk are perpendicular to each other when 3 a+2 b=7, the ratio of a to b is (x/2) The value of x is
Q. Vectors
a
i
^
+
b
j
^
+
k
^
and
2
i
^
−
3
j
^
+
4
k
^
are perpendicular to each other when
3
a
+
2
b
=
7
, the ratio of
a
to
b
is
2
x
The value of
x
is __
144
128
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Answer:
1
Solution:
For two perpendicular vectors
(
a
i
^
+
b
j
^
+
k
^
)
⋅
(
2
i
^
−
3
j
^
+
4
k
^
)
=
0
2
a
−
3
b
+
4
=
0
On solving,
2
a
−
3
b
=
−
4
Also given
3
a
+
2
b
=
7
We get
a
=
1
,
b
=
2
b
a
=
2
x
⇒
x
=
b
2
a
=
2
2
×
1
⇒
x
=
1