Q.
Vector A has a magnitude of 5 units, lies in the xy - plane and points in a direction 120∘ from the direction of increasing x . Vector B has a magnitude of 9 units and points along the z -axis. The magnitude of cross product A×B is
2704
185
AMUAMU 2012System of Particles and Rotational Motion
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Solution:
∣A∣=5,∣B∣=9
Vector B makes angle 90∘ from A A×B=∣A∣∣B∣sinθ =5×9sin90∘ =45