Vapour pressure of dilute aqueous solution of glucose is 750 mm of mercury at 373 K. The mole fraction of solute is

Question

Vapour pressure of dilute aqueous solution of glucose is 750 mm of mercury at 373 K. The mole fraction of solute is (A)  (1/76)  (B)  (1/7.6)  (C)  (1/38)  (D)  (1/10)

Tardigrade Admin · Accepted Answer

At 373 K (100° C ) V.P. of water, p °=760 mm Hg , ps=750 mm Hg (p°-ps/p°)=xB (760 -750/760)=xB xB=(1/76)

Q. Vapour pressure of dilute aqueous solution of glucose is $750 mm$ of mercury at $373 K$ . The mole fraction of solute is

$\frac{1}{76}$

$\frac{1}{7.6}$

$\frac{1}{38}$

$\frac{1}{10}$

At $373 K (10 0^{\circ} C)$ V.P.
of water, $p^{\circ} = 760 mm H g, p_{s} = 750 mm H g$
$\frac{p ^{\circ} - p _{s}}{p ^{\circ}} = x_{B}$
$\frac{760 - 750}{760} = x_{B}$
$x_{B} = \frac{1}{76}$

Q. Vapour pressure of dilute aqueous solution of glucose is 750mm of mercury at 373K. The mole fraction of solute is

761​

7.61​

381​

101​