"Vapour pressure of chloroform and dichloromethane at 298 K are 200 mm of Hg and 415 mm of Hg respectively". What is the vapour pressure of solution prepared by mixing 25.5 g of CHCl 3 and 40 g of CH 2 Cl 2 at 298 K ?

Question

"Vapour pressure of chloroform and dichloromethane at 298 K are 200 mm of Hg and 415 mm of Hg respectively". What is the vapour pressure of solution prepared by mixing 25.5 g of CHCl 3 and 40 g of CH 2 Cl 2 at 298 K ? (A) 347.9 mmHg (B) 300 mmHg (C) 200 mmHg (D) 147.9 mmHg

Tardigrade Admin · Accepted Answer

Molar mass of CH 2 Cl 2=12 × 1+1 × 2+35.5 × 2 =85 g mol -1 Molar mass of CHCl 3 =12 × 1+1 × 1+35.5 × 3 =119.5 g mol -1 Moles of CHCl 3=(25.5/119.5)=0.213 mol Moles of CH 2 Cl 2=(40 g /85 g mol -1)=0.47 mol Total number of moles =0.47+0.213=0.683 mol x CH 2 Cl 2 =(0.47 mol /0.683 mol )=0.688 x CHCl 2 =1.00-0.688=0.312 Using equation, p text total =p1°+(p2°-p1°) x2 =200+(415-200) × 0.688 =200+147.9 =347.9 mmHg

Q. "Vapour pressure of chloroform and dichloromethane at $298 K$ are $200 mm$ of $H g$ and $415 mm$ of $H g$ respectively".
What is the vapour pressure of solution prepared by mixing $25.5 g$ of $C H C l_{3}$ and $40 g$ of $C H_{2} C l_{2}$ at $298 K$ ?

$347.9 mm H g$

$300 mm H g$

$200 mm H g$

$147.9 mm H g$

Q. "Vapour pressure of chloroform and dichloromethane at 298K are 200mm of Hg and 415mm of Hg respectively". What is the vapour pressure of solution prepared by mixing 25.5g of CHCl3​ and 40g of CH2​Cl2​ at 298K ?

347.9mmHg

300mmHg

200mmHg

147.9mmHg

Q. "Vapour pressure of chloroform and dichloromethane at $298 K$ are $200 mm$ of $H g$ and $415 mm$ of $H g$ respectively".
What is the vapour pressure of solution prepared by mixing $25.5 g$ of $C H C l_{3}$ and $40 g$ of $C H_{2} C l_{2}$ at $298 K$ ?

$347.9 mm H g$

$300 mm H g$

$200 mm H g$

$147.9 mm H g$