Value of x in potash alum, K2SO4⋅ Alx(SO4)3⋅ 24H2O is

Question

Value of x in potash alum, K2SO4⋅ Alx(SO4)3⋅ 24H2O is (A) 4 (B) 1 (C) 2 (D) none of these

Tardigrade Admin · Accepted Answer

Potash alum K2SO4. Alx(SO4)3.24H2O It is a double salt <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/72ff517e75b3b6c20f82343abbb80454-.jpeg" /> Therefore, Al2(SO4)3- compound of Al3+ and SO2-4 On comparing, x=2 Hence, formula o f potash alum is K2SO4. Al2(SO4)3. 24H2O

Q. Value of $x$ in potash alum, $K_{2} S O_{4} \cdot A l_{x} (S O_{4})_{3} \cdot 24 H_{2} O$ is

$4$

$1$

$2$

none of these

Potash alum $K_{2} S O_{4} . A l_{x} (S O_{4})_{3} .24 H_{2} O$
It is a double salt
Therefore, $A l_{2} (S O_{4})_{3}$ - compound of $A l^{3 +}$ and $S O_{4}^{2 -}$ On comparing, $x = 2$
Hence, formula o f potash alum is
$K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O$

Q. Value of x in potash alum, K2​SO4​⋅Alx​(SO4​)3​⋅24H2​O is

4

1

2

none of these

Potash alum K2​SO4​.Alx​(SO4​)3​.24H2​O It is a double salt Therefore, Al2​(SO4​)3​- compound of Al3+ and SO42−​ On comparing, x=2 Hence, formula o f potash alum is K2​SO4​.Al2​(SO4​)3​.24H2​O

Q. Value of $x$ in potash alum, $K_{2} S O_{4} \cdot A l_{x} (S O_{4})_{3} \cdot 24 H_{2} O$ is

$4$

$1$

$2$

Potash alum $K_{2} S O_{4} . A l_{x} (S O_{4})_{3} .24 H_{2} O$
It is a double salt
Therefore, $A l_{2} (S O_{4})_{3}$ - compound of $A l^{3 +}$ and $S O_{4}^{2 -}$ On comparing, $x = 2$
Hence, formula o f potash alum is
$K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O$