Value of Lambda m ∞ for SrCl 2 in water at 25° from the following data: Conc. (mol/L) 0.25 1 Lambda m (Ω-1 cm 2 mol -1) 260 250

Question

Value of Lambda m ∞ for SrCl 2 in water at 25° from the following data: Conc. (mol/L) 0.25 1 Lambda m (Ω-1 cm 2 mol -1) 260 250 (A) 270 (B) 260 (C) 250 (D) 255

Tardigrade Admin · Accepted Answer

According to debye huckel onsagar equation

Λ_{C} = Λ_{\infty} - b C

260 = Λ_{\infty} - b 0.25

... (1)

250 = Λ_{\infty} - b 1

....(2)

e q^{n} (1) - e q^{n} (2)

than

10 - 0.5 b

b = 20

on putting value in eq

^{n} (1)

260 - Λ_{\infty} - 20 \times 0.5

Λ_{\infty} = 270

Conc. (mol/L)	0.25	1
$Λ_{m} (Ω^{- 1} c m^{2} m o l^{- 1})$	260	250

Q. Value of Λm∞​ for SrCl2​ in water at 25∘ from the following data : Conc. (mol/L) 0.25 1 Λm​(Ω−1cm2mol−1) 260 250

270

260

250

255

According to debye huckel onsagar equation ΛC​=Λ∞​−bC​ 260=Λ∞​−b0.25​ ... (1) 250=Λ∞​−b1​ ....(2) eqn(1)−eqn(2) than 10−0.5b b=20 on putting value in eq n(1) 260−Λ∞​−20×0.5 Λ∞​=270

Q. Value of $Λ_{m}^{\infty}$ for $S r C l_{2}$ in water at $2 5^{\circ}$ from the following data :

Conc. (mol/L) 0.25 1

$Λ_{m} (Ω^{- 1} c m^{2} m o l^{- 1})$ 260 250

According to debye huckel onsagar equation
$Λ_{C} = Λ_{\infty} - b C$
$260 = Λ_{\infty} - b 0.25$ ... (1)
$250 = Λ_{\infty} - b 1$ ....(2)
$e q^{n} (1) - e q^{n} (2)$
than $10 - 0.5 b$
$b = 20$
on putting value in eq $^{n} (1)$
$260 - Λ_{\infty} - 20 \times 0.5$
$Λ_{\infty} = 270$