Question

Value of equilibrium constant for the reaction,
$C{u}_{\left(aq\right)}^{2+}+S{n}_{\left(aq\right)}^{2+}\to S{n}_{\left(aq\right)}^{4+}+C{u}_{\left(s\right)}$ is (Given $E_{C{u}^{2+}/Cu}^{\circ }=0.34V,E_{S{n}^{4+}/S{n}^{2+}}^{\circ }=0.15V$)

• A. $1.64\times 10^3$
• B. $3.82\times 10^{16}$
• C. $2.69\times 10^6$
• D. $7.23\times 10^{12}$

Answer 1

Answer: (C)

$E_{\text{cell}}^{\circ }=E_{\text{cathode}}^{\circ }-E_{\text{anode}}^{\circ }=0.34-0.15=0.19V$
Applying, $E_{\text{cell}}^{\circ }=\frac{0.0591}{n}$ log $K$
log $K_c=\frac{0.19\times 2}{0.0591}=6.43$
Taking antilog, $K_c=2.69\times 10^6$