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Tardigrade
Question
Chemistry
Using the following thermochemical equations (i) S(rh)+3/2 O2(g) xrightarrow[]SO3(g) Δ H=-2x kJ mol-1 (ii) SO2(g)+1/2 O2(g) xrightarrowSO3(g) Δ H=-y kJ mol-1 . Find out the heat of formation of SO2(g) in kJ mol-1 .
Q. Using the following thermochemical equations
(i)
S
(
r
h
)
+
3/2
O
2
(
g
)
S
O
3
(
g
)
Δ
H
=
−
2
x
k
J
m
o
l
−
1
(ii)
S
O
2
(
g
)
+
1/2
O
2
(
g
)
S
O
3
(
g
)
Δ
H
=
−
y
k
J
m
o
l
−
1
.
Find out the heat of formation of
S
O
2
(
g
)
in
k
J
m
o
l
−
1
.
2725
240
KEAM
KEAM 2008
Thermodynamics
Report Error
A
(
2
x
+
y
)
11%
B
(
x
+
y
)
11%
C
(
2
x
/
y
)
11%
D
(
y
−
2
x
)
44%
E
(
2
x
−
y
)
44%
Solution:
Given
S
(
r
h
)
+
2
3
O
2
(
g
)
S
O
3
(
g
)
;
Δ
H
=
−
2
x
k
J
m
o
l
−
1
...(i)
S
O
2
(
g
)
+
2
1
O
2
(
g
)
S
O
3
(
g
)
;
Δ
H
=
−
y
k
J
m
o
l
−
1
...(ii)
S
(
s
)
+
O
2
(
g
)
S
O
2
(
g
)
;
Δ
H
=
?
Subtract Eq (ii) from Eq (i)
a
S
(
r
h
)
+
2
3
O
2
(
g
)
S
O
3
(
g
)
;
Δ
H
=
−
2
x
k
J
m
o
l
−
1
S
O
2
(
g
)
+
2
1
O
2
(
g
)
S
O
3
(
g
)
;
Δ
H
=
−
y
k
J
m
o
l
−
1
−
−
−
+
S
(
r
h
)
+
(
2
3
−
2
1
)
O
2
(
g
)
S
O
2
(
g
)
;
Δ
H
=
(
−
2
x
+
y
)
k
J
m
o
l
−
1
S
(
r
h
)
+
O
2
(
g
)
S
O
2
(
g
)
;
Δ
H
=
(
y
−
2
x
)
k
J
m
o
l
−
1