Question

Using the following data
Mass of hydrogen atom $=1.00783u$
Mass of neutron $=1.00867u$
Mass of nitrogen atom ${}_7{N}^{14}=14.00307u$
The calculated value of the binding energy of the nucleus of the nitrogen atom ${}_7{N}^{14}$ is close to

• A. $56MeV$
• B. $98MeV$
• C. $104MeV$
• D. $112MeV$

Answer 1

Answer: (C)

The binding energy of nucleus may be defined as the energy equivalent to the mass defect of the nucleus.
If $\Delta m$ is mass defect than according to Einstein's mass energy relation.
Binding Energy
$=\Delta m{c}^2=Z{m}_p+A-Z{m}_n-M{c}^2$
$=7\times 1.00783+7\times 1.00867-14.00307c^2$
or $BE=0.1124\times 931.5MeV$
or $BE\approx 104.6MeV$