Using the following data Mass hydrogen atom = 1.00783 u Mass of neutron = 1.00867 u Mass of nitrogen atom ( 7N14 )= 14.00307 u The calculated value of the binding energy of the nucleus of the nitrogen atom ( 7N14 ) is close to

Question

Using the following data Mass hydrogen atom = 1.00783 u Mass of neutron = 1.00867 u Mass of nitrogen atom ( 7N14 )= 14.00307 u The calculated value of the binding energy of the nucleus of the nitrogen atom ( 7N14 ) is close to (A) 56MeV (B) 98MeV (C) 104MeV (D) 112MeV

Tardigrade Admin · Accepted Answer

The binding energy of nucleus may be defined as the energy equivalent to the mass defect of the nucleus.
If

Δ m

is mass defect then according to Einstein's mass-energy relation.
Binding Energy

= Δ m c^{2} = [{Z m_{p} + (A - Z) m_{n}} - M] c^{2}

= (7 \times 1.00783 + 7 \times 1.00867 - 14.00307) c^{2}

or BE = 0.1124 \times 931.5 M e V

or

BE = 104.6 M e V

Q. Using the following data
Mass hydrogen atom = $1.00783 u$
Mass of neutron = $1.00867 u$
Mass of nitrogen atom ( $_{7} N^{14}$ )= $14.00307 u$
The calculated value of the binding energy of the nucleus of the nitrogen atom ( $_{7} N^{14}$ ) is close to

$56 M e V$

$98 M e V$

$104 M e V$

$112 M e V$

Q. Using the following data Mass hydrogen atom = 1.00783u Mass of neutron = 1.00867u Mass of nitrogen atom ( 7​N14 )= 14.00307u The calculated value of the binding energy of the nucleus of the nitrogen atom ( 7​N14 ) is close to

56MeV

98MeV

104MeV

112MeV

Q. Using the following data
Mass hydrogen atom = $1.00783 u$
Mass of neutron = $1.00867 u$
Mass of nitrogen atom ( $_{7} N^{14}$ )= $14.00307 u$
The calculated value of the binding energy of the nucleus of the nitrogen atom ( $_{7} N^{14}$ ) is close to

$56 M e V$

$98 M e V$

$104 M e V$

$112 M e V$