Using the data provided, calculate the multiple bond energy (.kJmol- 1.) of a C≡ C bond in C2H2 . That energy is (take the bond energy of a C-H bond as 350 kJ mol- 1 ). 2C(s)+H2(g) arrow C2H2(g)Δ H=225 kJmol- 1 2C(.s.) arrow 2C(.g.)Δ H=1410 kJmol- 1 H2(g) arrow 2H(g)Δ H=330 kJmol- 1

Question

Using the data provided, calculate the multiple bond energy (.kJmol- 1.) of a C≡ C bond in C2H2 . That energy is (take the bond energy of a C-H bond as 350 kJ mol- 1 ). 2C(s)+H2(g) arrow C2H2(g)Δ H=225 kJmol- 1 2C(.s.) arrow 2C(.g.)Δ H=1410 kJmol- 1 H2(g) arrow 2H(g)Δ H=330 kJmol- 1 (A) 837 (B) 1165 (C) 815 (D) 865

Tardigrade Admin · Accepted Answer

Let x be the bond energy of C≡ C , it can be find out as follows 2C(.s.)+H2(.g.) arrow C2H2(.g.) Δ H= Sigma [(B . E .)r e a c t a n t - (B . E .)p r o d u c t ] 1410+330-(x + 2 × 350)=225 x=815 kJmol- 1

$837$

$1165$

$815$

$865$

Let x be the bond energy of $C \equiv C$ , it can be find out as follows
$2 C (s) + H_{2} (g) \to C_{2} H_{2} (g)$
$Δ H = Σ [(B . E .)_{re a c t an t} - (B . E .)_{p ro d u c t}]$
$1410 + 330 - (x + 2 \times 350) = 225$
$x = 815$ $k J m o l^{- 1}$

Q. Using the data provided, calculate the multiple bond energy (kJmol−1) of a C≡C bond in C2​H2​ . That energy is (take the bond energy of a C−H bond as 350kJ mol−1 ). 2C(s)+H2​(g)→C2​H2​(g)ΔH=225 kJmol−1 2C(s)→2C(g)ΔH=1410 kJmol−1 H2​(g)→2H(g)ΔH=330 kJmol−1

837

1165

815

865

Let x be the bond energy of C≡C , it can be find out as follows 2C(s)+H2​(g)→C2​H2​(g) ΔH=Σ[(B.E.)reactant​−(B.E.)product​] 1410+330−(x+2×350)=225 x=815 kJmol−1

$837$

$1165$

$815$

$865$

Let x be the bond energy of $C \equiv C$ , it can be find out as follows
$2 C (s) + H_{2} (g) \to C_{2} H_{2} (g)$
$Δ H = Σ [(B . E .)_{re a c t an t} - (B . E .)_{p ro d u c t}]$
$1410 + 330 - (x + 2 \times 350) = 225$
$x = 815$ $k J m o l^{- 1}$