Using h vi f=Eni-Enf, we get (1/λi f)=R((1/nf2)-(1/ni2)), the value of Rydberg constant is given by

Question

Using h vi f=Eni-Enf, we get (1/λi f)=R((1/nf2)-(1/ni2)), the value of Rydberg constant is given by (A) R=(m e4/8 ε02 h3 c) (B) R=(m e4/4 ε02 h3 c) (C) R=(m e4/4 ε02 h2 c2) (D) R=(m e2/4 π ε0 ⋅ h2 c)

Tardigrade Admin · Accepted Answer

Correct answer is (a) R=(m e4/8 ε02 h3 c)

Q. Using $h v_{i f} = E_{n_{i}} - E_{n_{f}}$ , we get $\frac{1}{λ _{i f}} = R (\frac{1}{n _{f}^{2}} - \frac{1}{n _{i}^{2}})$ , the value of Rydberg constant is given by

$R = \frac{m e ^{4}}{8 ε _{0}^{2} h ^{3} c}$

$R = \frac{m e ^{4}}{4 ε _{0}^{2} h ^{3} c}$

$R = \frac{m e ^{4}}{4 ε _{0}^{2} h ^{2} c ^{2}}$

$R = \frac{m e ^{2}}{4 π ε _{0} \cdot h ^{2} c}$

Correct answer is (a) $R = \frac{m e ^{4}}{8 ε _{0}^{2} h ^{3} c}$

Q. Using hvif​=Eni​​−Enf​​, we get λif​1​=R(nf2​1​−ni2​1​), the value of Rydberg constant is given by

R=8ε02​h3cme4​

R=4ε02​h3cme4​

R=4ε02​h2c2me4​

R=4πε0​⋅h2cme2​