Question

$\underset{x\to \infty }{\mathrm{Lim}}\frac{{\left(\underset{0}{\overset{x}{\int }}{e}^{t^2}dt\right)}^2}{\underset{0}{\overset{x}{\int }}{e}^{2t^2}dt}$ is equal to

• A. 0
• B. $e$
• C. $e^2$
• D. 1

Answer 1

Answer: (A)

Correct answer is (a) 0