Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
underset text(A)PHCONH2 xrightarrow[KOBr] (B) xrightarrow[MeOH] (C) Product (C) is
Q.
(A)
P
H
CON
H
2
K
OB
r
(
B
)
M
e
O
H
(
C
)
Product (C) is
1651
224
Aldehydes Ketones and Carboxylic Acids
Report Error
A
P
h
N
H
2
B
P
h
N
H
C
OOM
e
C
P
h
N
H
COOP
h
D
None of these
Solution:
Hofinann bromamide reactions. The product
(
P
h
−
N
=
C
=
O
)
reacts with
M
e
O
H
to give urethane
(
P
h
−
N
H
−
COOM
e
)
.