1. Tardigrade
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  3. Chemistry
  4. underset text(A)PHCONH2 xrightarrow[KOBr] (B) xrightarrow[MeOH] (C) Product (C) is

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Q. $\underset{\text{(A)}}{PHCONH_2} \xrightarrow[KOBr]{} (B) \xrightarrow[{MeOH}]{} (C)$ Product (C) is

Aldehydes Ketones and Carboxylic Acids

Solution:

Hofinann bromamide reactions. The product $\left(Ph-N=C=O\right)$ reacts with $MeOH$ to give urethane $\left(Ph-NH-COOMe\right).$