Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Underlined carbon is sp3 hybridised in:
Q. Underlined carbon is
s
p
3
hybridised in:
1966
222
Jamia
Jamia 2005
Report Error
A
C
H
3
C
H
=
C
H
2
B
C
H
3
C
H
2
N
H
2
C
C
H
3
C
ON
H
2
D
C
H
3
C
H
2
C
N
Solution:
Correct answer is (b)
C
H
3
C
H
2
N
H
2