Under the same conditions, how many mL of 1 M KOH and 0.5 M H2SO4 solutions, respectively, when mixed to form at a total volume of 100 mL produces the highest rise in temperature?

Question

Under the same conditions, how many mL of 1 M KOH and 0.5 M H2SO4 solutions, respectively, when mixed to form at a total volume of 100 mL produces the highest rise in temperature? (A) 67, 33 (B) 33, 67 (C) 40, 60 (D) 50, 50

Tardigrade Admin · Accepted Answer

underset2 m o l2 K O H (. a q .)+ underset1 m o lH2 S O4 (. a q .) arrow K2SO4+H2O+Heat Thus, maximum heat is liberated if 2 mol of KOH reacts with 1 mol H2SO4 (or if the ratio of the amounts of KOH to H2SO4 is 2: 1). Let x = volume of KOH, then 100 mL - x = volume of H2SO4 Number of mmol KOH =x× 1 mmol of KOH Number of mmol of H2SO4=(.100-x.)× 0.5 mmol of H2SO4 Maximum heat is liberated if (x m m o l o f K O H/(. 100 - x .) × 0.5 m m o l H2 S O4)=(2/1) So textx text= text50 textmL

Q. Under the same conditions, how many mL of 1 M KOH and 0.5 M H2​SO4​ solutions, respectively, when mixed to form at a total volume of 100 mL produces the highest rise in temperature?

67, 33

33, 67

40, 60

50, 50

Q. Under the same conditions, how many mL of 1 M KOH and 0.5 M $H_{2} S O_{4}$ solutions, respectively, when mixed to form at a total volume of 100 mL produces the highest rise in temperature?