Uncertainty in position of a particle of 25 g in space is 10-5 m. Hence, uncertainty in velocity( ms -1) is (Planck's constant h=6.6 × 10-34 Js ):

Question

Uncertainty in position of a particle of 25 g in space is 10-5 m. Hence, uncertainty in velocity( ms -1) is (Planck's constant h=6.6 × 10-34 Js ):  (A) 2.1 × 10-28 (B) 2.1 × 10-34 (C) 0.5 × 10-34 (D) 5.0 × 10-24

Tardigrade Admin · Accepted Answer

Heisenberg uncertainty principle Δ x ⋅ m Δ v ≈ (h/4 π) uncertainty in velocity Δ v =(h/4 × 3.14 × Δ x × m) =(6.626 × 10-34/4 × 3.14 × 0.025 × 10-5) =2.1 × 10-28

Q. Uncertainty in position of a particle of $25 g$ in space is $1 0^{- 5} m$ . Hence, uncertainty in velocity $(m s^{- 1})$ is (Planck's constant $h = 6.6 \times 1 0^{- 34} J s) :$

$2.1 \times 1 0^{- 28}$

$2.1 \times 1 0^{- 34}$

$0.5 \times 1 0^{- 34}$

$5.0 \times 1 0^{- 24}$

Heisenberg uncertainty principle

$Δ x \cdot m Δ v \approx \frac{h}{4 π}$

uncertainty in velocity

$Δ v = \frac{h}{4 \times 3.14 \times Δ x \times m}$

$= \frac{6.626 \times 1 0 ^{- 34}}{4 \times 3.14 \times 0.025 \times 1 0 ^{- 5}}$

$= 2.1 \times 1 0^{- 28}$

Q. Uncertainty in position of a particle of 25g in space is 10−5m. Hence, uncertainty in velocity(ms−1) is (Planck's constant h=6.6×10−34Js):

2.1×10−28

2.1×10−34

0.5×10−34

5.0×10−24