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- Question
- Physics
- U-tube moves with a constant speed v parallel to the surface of a stationary liquid. The cross-section area of the lower part of the tube lowered into the liquid, is equal to S1 and that of the top part located over the liquid is S2 . Friction and formation of waves should be neglected. The density of the fluid is ρ . Neglect difference in heights at both the openings of the tube. <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-wyhmc75d0e65.png /> The velocity of the liquid coming out of the top part as seen by an observer on the ground will be
Q.
U-tube moves with a constant speed parallel to the surface of a stationary liquid. The cross-section area of the lower part of the tube lowered into the liquid, is equal to and that of the top part located over the liquid is . Friction and formation of waves should be neglected. The density of the fluid is . Neglect difference in heights at both the openings of the tube.
The velocity of the liquid coming out of the top part as seen by an observer on the ground will be
Solution: