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Tardigrade
Question
Physics
Two waves of wavelengths 50 cm and 51 cm produced 12 beats per sec. The velocity of sound is
Q. Two waves of wavelengths
50
c
m
and
51
c
m
produced
12
beats per sec. The velocity of sound is
3813
232
JIPMER
JIPMER 2013
Waves
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A
340 ms
8%
B
331 ms
11%
C
306 m s
69%
D
360 ms
12%
Solution:
Number of beats produced per sec.
=
v
1
−
v
2
=
λ
1
v
−
λ
2
v
12
=
v
[
50
1
−
51
1
]
or,
12
=
50
×
51
v
×
1
or,
v
=
12
×
50
×
51
c
m
/
s
=
306
m
/
s
.