Two vibrating tuning forks produce waves given by y1=4 sin 500 π t and y2=2 sin 506 π t. Number of beats produced per minute is

Question

Two vibrating tuning forks produce waves given by y1=4 sin 500 π t and y2=2 sin 506 π t. Number of beats produced per minute is (A) 360 (B) 180 (C) 60 (D) 3

Tardigrade Admin · Accepted Answer

Y1=4 sin 500 π t, Y2=2 sin 506 π t ω1=500 π, ω1=2 π v, v1=250, v2=253 v=v2-v1=253-250=3 beats / s Number of beats per minute =3 × 60=180

Q. Two vibrating tuning forks produce waves given by $y_{1} = 4 sin 500 π t$ and $y_{2} = 2 sin 506 π t$ . Number of beats produced per minute is

360

180

60

3

$Y_{1} = 4 sin 500 π t, Y_{2} = 2 sin 506 π t$
$ω_{1} = 500 π, ω_{1} = 2 π v, v_{1} = 250, v_{2} = 253$
$v = v_{2} - v_{1} = 253 - 250 = 3$ beats $/ s$
Number of beats per minute $= 3 \times 60 = 180$

Q. Two vibrating tuning forks produce waves given by y1​=4sin500πt and y2​=2sin506πt. Number of beats produced per minute is

360

180

60

3

Y1​=4sin500πt,Y2​=2sin506πt ω1​=500π,ω1​=2πv,v1​=250,v2​=253 v=v2​−v1​=253−250=3 beats /s Number of beats per minute =3×60=180

Q. Two vibrating tuning forks produce waves given by $y_{1} = 4 sin 500 π t$ and $y_{2} = 2 sin 506 π t$ . Number of beats produced per minute is

$Y_{1} = 4 sin 500 π t, Y_{2} = 2 sin 506 π t$
$ω_{1} = 500 π, ω_{1} = 2 π v, v_{1} = 250, v_{2} = 253$
$v = v_{2} - v_{1} = 253 - 250 = 3$ beats $/ s$
Number of beats per minute $= 3 \times 60 = 180$