Two vibrating tuning forks produce progressive waves given by y1 = 4 sin 500 π t and y2 = 2 sin 506 π t. Number of beats produced perminute is :

Question

Two vibrating tuning forks produce progressive waves given by y1 = 4 sin 500 π t and y2 = 2 sin 506 π t. Number of beats produced perminute is : (A) 360 (B) 180 (C) 120 (D) 30

Tardigrade Admin · Accepted Answer

Number of beats per second = n2 - n1 = 3 (∴ n1 = 250, n2 = 253 ) Number of bears produced per minute= 3 × 60 = 180

Q. Two vibrating tuning forks produce progressive waves given by $y_{1} = 4 sin 500 π t$ and $y_{2} = 2 sin 506 π t$ . Number of beats produced perminute is :

360

180

120

30

Number of beats per second = $n_{2} - n_{1} = 3 (∴ n_{1} = 250, n_{2} = 253)$
Number of bears produced per minute $= 3 \times 60 = 180$

Q. Two vibrating tuning forks produce progressive waves given by y1​=4sin500πt and y2​=2sin506πt. Number of beats produced perminute is :

360

180

120

30

Number of beats per second = n2​−n1​=3(∴n1​=250,n2​=253) Number of bears produced per minute=3×60=180

Q. Two vibrating tuning forks produce progressive waves given by $y_{1} = 4 sin 500 π t$ and $y_{2} = 2 sin 506 π t$ . Number of beats produced perminute is :

Number of beats per second = $n_{2} - n_{1} = 3 (∴ n_{1} = 250, n_{2} = 253)$
Number of bears produced per minute $= 3 \times 60 = 180$