Two unbiased six faced dice are thrown. The probability that the sum of the numbers on their faces is a prime number greater than 5 is

Question

Two unbiased six faced dice are thrown. The probability that the sum of the numbers on their faces is a prime number greater than 5 is (A) (1/6) (B) (1/2) (C) (2/9) (D) (4/9)

Tardigrade Admin · Accepted Answer

P(7 + 11) = (6 + 2/36) = (8/36) = (2/9)

Q. Two unbiased six faced dice are thrown. The probability that the sum of the numbers on their faces is a prime number greater than 5 is

$\frac{1}{6}$

$\frac{1}{2}$

$\frac{2}{9}$

$\frac{4}{9}$

$P (7 + 11) = \frac{6 + 2}{36} = \frac{8}{36} = \frac{2}{9}$