Two unbiased dice are thrown simultaneously- The probability to get a sum more than 8 is

Question

Two unbiased dice are thrown simultaneously- The probability to get a sum more than 8 is (A)  5/36  (B)  5/18  (C)  5/12  (D)  2/9

Tardigrade Admin · Accepted Answer

Total number of outcomes = 36 Favourable outcomes are (3,6), (4,5), (5,5), (6,5), (6,4), (4,6), (6,3), (5,4), (6,6), (5,6). No of favourable outcomes = 10 ∴ Required probability =(10/36)=(5/18)

Q. Two unbiased dice are thrown simultaneously- The probability to get a sum more than 8 is

$5/36$

$5/18$

$5/12$

$2/9$

Total number of outcomes = 36
Favourable outcomes are $(3, 6), (4, 5), (5, 5),$
$(6, 5), (6, 4), (4, 6), (6, 3), (5, 4), (6, 6), (5, 6) .$
No of favourable outcomes = 10
$∴$ Required probability
$= \frac{10}{36} = \frac{5}{18}$

Q. Two unbiased dice are thrown simultaneously- The probability to get a sum more than 8 is

5/36

5/18

5/12

2/9

Total number of outcomes = 36 Favourable outcomes are (3,6),(4,5),(5,5), (6,5),(6,4),(4,6),(6,3),(5,4),(6,6),(5,6). No of favourable outcomes = 10 ∴ Required probability =3610​=185​

$5/36$

$5/18$

$5/12$

$2/9$

Total number of outcomes = 36
Favourable outcomes are $(3, 6), (4, 5), (5, 5),$
$(6, 5), (6, 4), (4, 6), (6, 3), (5, 4), (6, 6), (5, 6) .$
No of favourable outcomes = 10
$∴$ Required probability
$= \frac{10}{36} = \frac{5}{18}$