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Q. Two unbiased dice are thrown simultaneously- The probability to get a sum more than 8 is

J & K CETJ & K CET 2006

Solution:

Total number of outcomes = 36
Favourable outcomes are $ (3,6),\,(4,5),\,(5,5), $
$ (6,5),\,(6,4),\,(4,6),\,(6,3),\,(5,4),\,(6,6),\,(5,6). $
No of favourable outcomes = 10
$ \therefore $ Required probability
$ =\frac{10}{36}=\frac{5}{18} $