Two tuning forks of frequencies 256 Hz and 258 Hz are sounded together. The time interval between consecutive maxima heard by the observer is

Question

Two tuning forks of frequencies 256 Hz and 258 Hz are sounded together. The time interval between consecutive maxima heard by the observer is (A) 2 s (B) 0.5 s (C) 250 s (D) 252 s

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6095e711acb78a11602bd297784cb9c9-.png" /> Beat frequency =258 Hz -256 Hz =2 per second Hence time-interval between consecutive maxima =(1/2) s =0.5 s

Q. Two tuning forks of frequencies $256 Hz$ and $258 Hz$ are sounded together. The time interval between consecutive maxima heard by the observer is

2 s

0.5 s

250 s

252 s

Beat frequency $= 258 Hz - 256 Hz$
$= 2$ per second
Hence time-interval between consecutive maxima $= \frac{1}{2} s$
$= 0.5 s$

Q. Two tuning forks of frequencies 256Hz and 258Hz are sounded together. The time interval between consecutive maxima heard by the observer is

2 s

0.5 s

250 s

252 s

Beat frequency =258Hz−256Hz =2 per second Hence time-interval between consecutive maxima =21​s =0.5s

Q. Two tuning forks of frequencies $256 Hz$ and $258 Hz$ are sounded together. The time interval between consecutive maxima heard by the observer is

Beat frequency $= 258 Hz - 256 Hz$
$= 2$ per second
Hence time-interval between consecutive maxima $= \frac{1}{2} s$
$= 0.5 s$