Two tuning forks have frequencies 380 and 384 Hz respectively. When they are sounded together, they produce 4 beats. After hearing the maximum sound, how long will it take to hear the minimum sound

Question

Two tuning forks have frequencies 380 and 384 Hz respectively. When they are sounded together, they produce 4 beats. After hearing the maximum sound, how long will it take to hear the minimum sound (A) (1/2) s (B) (1/4) s (C) (1/8) s (D) (1/16) s

Tardigrade Admin · Accepted Answer

Beat period T=(1/n1 ∼ n2) =(1/384-380)=(1/4) sec. Hence minimum time interval between maxima and minima t=(T/2)=(1/8) sec

Q. Two tuning forks have frequencies 380 and $384 Hz$ respectively. When they are sounded together, they produce 4 beats. After hearing the maximum sound, how long will it take to hear the minimum sound

$\frac{1}{2} s$

$\frac{1}{4} s$

$\frac{1}{8} s$

$\frac{1}{16} s$

Beat period $T = \frac{1}{n _{1} \sim n _{2}}$
$= \frac{1}{384 - 380} = \frac{1}{4} sec .$
Hence minimum time interval between maxima and minima
$t = \frac{T}{2} = \frac{1}{8} sec$

Q. Two tuning forks have frequencies 380 and 384Hz respectively. When they are sounded together, they produce 4 beats. After hearing the maximum sound, how long will it take to hear the minimum sound

21​s

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