Two travelling waves produces a standing wave represented by equation, y =1.0 mm cos (1.57 cm -1) x sin (78.5 s -1) t The node closest to the origin in the region x0 will bc at x = . cm

Question

Two travelling waves produces a standing wave represented by equation, y =1.0 mm cos (1.57 cm -1) x sin (78.5 s -1) t The node closest to the origin in the region x>0 will bc at x = . cm (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

For node cos (1.57 cm -1) x =0 (1.57 cm -1) x =(π/2) x =(π/2(1.57)) cm =1 cm

Q. Two travelling waves produces a standing wave represented by equation,
$y = 1.0 mm cos (1.57 c m^{- 1}) x sin (78.5 s^{- 1}) t$
The node closest to the origin in the region $x > 0$ will bc at $x =$ ______. $c m$

For node
$cos (1.57 c m^{- 1}) x = 0$
$(1.57 c m^{- 1}) x = \frac{π}{2}$
$x = \frac{π}{2 ( 1.57 )} c m = 1 c m$

Q. Two travelling waves produces a standing wave represented by equation, y=1.0mmcos(1.57cm−1)xsin(78.5s−1)t The node closest to the origin in the region x>0 will bc at x= ______.cm

For node cos(1.57cm−1)x=0 (1.57cm−1)x=2π​ x=2(1.57)π​cm=1cm

Q. Two travelling waves produces a standing wave represented by equation,
$y = 1.0 mm cos (1.57 c m^{- 1}) x sin (78.5 s^{- 1}) t$
The node closest to the origin in the region $x > 0$ will bc at $x =$ ______. $c m$

For node
$cos (1.57 c m^{- 1}) x = 0$
$(1.57 c m^{- 1}) x = \frac{π}{2}$
$x = \frac{π}{2 ( 1.57 )} c m = 1 c m$