Two trains, each 50 m long are travelling in opposite direction with velocity 10 m/s-1 and 15 m/s-1. The time of crossing is:

Question

Two trains, each 50 m long are travelling in opposite direction with velocity 10 m/s-1 and 15 m/s-1. The time of crossing is: (A)  4s  (B)  2 s  (C)  2√3 s  (D)  4√3 s

Tardigrade Admin · Accepted Answer

From the formula textTime text=( texttotal textdistance/ textrelaive textvelocity) =(50+50/10+15) =(100/20) = 4s

Q. Two trains, each $50 m$ long are travelling in opposite direction with velocity $10 m / s^{- 1}$ and $15 m / s^{- 1}$ . The time of crossing is:

$4 s$

$2 s$

$23 s$

$43 s$

From the formula $Time = \frac{total distance}{relaive velocity}$ $= \frac{50 + 50}{10 + 15} = \frac{100}{20} = 4 s$

Q. Two trains, each 50m long are travelling in opposite direction with velocity 10m/s−1 and 15m/s−1. The time of crossing is:

4s

2s

23​s

43​s