Two thermometers X and Y have ice points marked at 15o and 25o and steam points marked as 75o and 125o , respectively. When thermometer X measures the temperature of a bath as 60o on it, what would thermometer Y read when it is used to measure the temperature of the same bath?

Question

Two thermometers X and Y have ice points marked at 15o and 25o and steam points marked as 75o and 125o , respectively. When thermometer X measures the temperature of a bath as 60o on it, what would thermometer Y read when it is used to measure the temperature of the same bath? (A) 60o (B) 75o (C) 100o (D) 90o

Tardigrade Admin · Accepted Answer

(60 - 15/75 - 15)=(Y - 25/125 - 25) (45/60)=(Y - 25/100) Y=(100/60)× 45+25=100o

$6 0^{o}$

$7 5^{o}$

$10 0^{o}$

$9 0^{o}$

$\frac{60 - 15}{75 - 15} = \frac{Y - 25}{125 - 25}$
$\frac{45}{60} = \frac{Y - 25}{100}$
$Y = \frac{100}{60} \times 45 + 25 = 10 0^{o}$

Q. Two thermometers X and Y have ice points marked at 15o and 25o and steam points marked as 75o and 125o , respectively. When thermometer X measures the temperature of a bath as 60o on it, what would thermometer Y read when it is used to measure the temperature of the same bath?

60o

75o

100o

90o

75−1560−15​=125−25Y−25​ 6045​=100Y−25​ Y=60100​×45+25=100o

$6 0^{o}$

$7 5^{o}$

$10 0^{o}$

$9 0^{o}$

$\frac{60 - 15}{75 - 15} = \frac{Y - 25}{125 - 25}$
$\frac{45}{60} = \frac{Y - 25}{100}$
$Y = \frac{100}{60} \times 45 + 25 = 10 0^{o}$