Q.
Two stars each of mass m and radius R approach each other to collide head-on. Initially the stars are at a distance r(>>R). Assuming their speeds to be negligible at this distance of separation, the speed with which the stars collide is
Since the speeds of the stars are negligible when they are at a distance of r, the initial kinetic energy of the system is zero. Therefore, initial total energy of the system is Ei=KE+PE=0+(−rGmm)...(i)
where m represents the mass of each star and r the initial separation between them.
When two stars collide, their centres will be at a distance twice the radius of a star i.e.2R. Let v be the speed with which two stars collide. Then total energy of the system at the instant of their collision is Ef=(21mv2)×2+(−2RGmm)=mv2−2RGMm
According to law of conservation of energy, Ef=Ei ∴mv2−2RGmm=−rGmm
or v2=Gm(2R1−r1)
or v=Gm(2R1−r1)