Two springs of spring constants k1 and k2 are joined in series. The effective spring constant of the combination is given by

Question

Two springs of spring constants k1 and k2 are joined in series. The effective spring constant of the combination is given by (A)  √ k1 k2 (B) (k1 + k2) / 2 (C)  k1 + k2  (D)  k1 k2 / (k1 + k2)

Tardigrade Admin · Accepted Answer

Two springs of spring constant k 1 and k 2 are joined in series. The effective spring constant of the combination is - We know using hooke's law ( f 1/ k 1)= x 1 ( f 2/ k 2)= x 2 X =( f 1/ k 1)+( f 2/ k 2) X=(F/k1)+(F/k2) X=F((1/k1)+(1/k2)) X=F[((k1+k2)/k1 k2)] F =( k 1 k 2/( k 1+ k 2)) X Therefore, k =( k 1 k 2/( k 1+ k 2))

Q. Two springs of spring constants $k_{1}$ and $k_{2}$ are joined in series. The effective spring constant of the combination is given by

$k_{1} k_{2}$

$(k_{1} + k_{2}) /2$

$k_{1} + k_{2}$

$k_{1} k_{2} / (k_{1} + k_{2})$

Q. Two springs of spring constants k1​ and k2​ are joined in series. The effective spring constant of the combination is given by

k1​k2​​

(k1​+k2​)/2

k1​+k2​

k1​k2​/(k1​+k2​)

Q. Two springs of spring constants $k_{1}$ and $k_{2}$ are joined in series. The effective spring constant of the combination is given by

$k_{1} k_{2}$

$(k_{1} + k_{2}) /2$

$k_{1} + k_{2}$

$k_{1} k_{2} / (k_{1} + k_{2})$