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Physics
Two springs of force constant 1000 N/m and 2000 N/m are streched by same force. The ratio of their respective potential energies is
Q. Two springs of force constant 1000 N/m and 2000 N/m are streched by same force. The ratio of their respective potential energies is
2300
238
MGIMS Wardha
MGIMS Wardha 2009
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A
2 : 1
B
1 : 2
C
4 : 1
D
1 : 4
Solution:
Forces are same
∴
k
2
x
2
k
1
x
1
=
1
⇒
k
2
k
1
=
x
1
x
2
x
1
x
2
=
2000
1000
=
2
1
U
2
U
1
=
2
1
k
2
x
2
2
2
1
k
1
x
1
2
=
k
2
k
1
[
x
2
x
1
]
2
=
2
1
×
4
=
1
2
=
2
:
1