Question

Two sound waves have phase difference of $60^{\circ }$, then they will have the path difference of:

• A. $3\lambda$
• B. $\frac{\lambda }{3}$
• C. $\frac{\lambda }{6}$
• D. $\lambda$

Answer 1

Answer: (C)

We know that
Phase difference $=\frac{2\pi }{\lambda }\times$ path difference
where $\lambda$ is wavelength.
Given, phase difference $\theta =60^{\circ }=\frac{\pi }{3}rad$
Hence, path difference $=\frac{\lambda }{2\pi }\times \frac{\pi }{3}=\frac{\lambda }{6}$