Question

Two sound waves have phase difference of $60^{\circ}$, then they will have the path difference of:

• A. $3 \lambda$
• B. $\frac{\lambda}{3}$
• C. $\frac{\lambda}{6}$
• D. $\lambda$

Answer 1

Answer: (C)

We know that
Phase difference $=\frac{2 \pi}{\lambda} \times$ path difference
where $\lambda$ is wavelength.
Given, phase difference $\theta=60^{\circ}=\frac{\pi}{3} rad$
Hence, path difference $=\frac{\lambda}{2 \pi} \times \frac{\pi}{3}=\frac{\lambda}{6}$