Two solenoids of same cross-sectional area have their lengths and number of turns in ratio of 1: 2. The ratio of self-inductance of two solenoids is

Question

Two solenoids of same cross-sectional area have their lengths and number of turns in ratio of 1: 2. The ratio of self-inductance of two solenoids is (A) 1: 1 (B) 1: 2 (C) 2: 1 (D) 1: 4

Tardigrade Admin · Accepted Answer

From L =(μ0 N 2 A /1) ⇒ L propto ( N 2/1) we get, ( L 1/ L 2) =((1 / 2)2/1 / 2)=(1/2)

Q. Two solenoids of same cross-sectional area have their lengths and number of turns in ratio of $1 : 2$ . The ratio of self-inductance of two solenoids is

1 : 1

1 : 2

2 : 1

1 : 4

From $L = \frac{μ _{0} N ^{2} A}{1}$
$\Rightarrow L \propto \frac{N ^{2}}{1}$
we get, $\frac{L _{1}}{L _{2}}$
$= \frac{( 1/2 ) ^{2}}{1/2} = \frac{1}{2}$

Q. Two solenoids of same cross-sectional area have their lengths and number of turns in ratio of 1:2. The ratio of self-inductance of two solenoids is