Two satellites A and B go around the earth in circular orbits at heights of RA and RB respectively from the surface of the earth. Assuming the earth to be a uniform sphere of radius Re, the ratio of the magnitudes of their orbital velocities is :-

Question

Two satellites A and B go around the earth in circular orbits at heights of RA and RB respectively from the surface of the earth. Assuming the earth to be a uniform sphere of radius Re, the ratio of the magnitudes of their orbital velocities is :- (A) √(RB/RA) (B) (RB + Re/RA + Re) (C) √(RB + Re/RA + Re) (D) ((RA/RB))2

Tardigrade Admin · Accepted Answer

since, orbital velocity is inversely proportional to the square root of the radius of the orbit, (vA/vB)=√(RB + Re/RA + Re)

Q. Two satellites $A$ and $B$ go around the earth in circular orbits at heights of $R_{A}$ and $R_{B}$ respectively from the surface of the earth. Assuming the earth to be a uniform sphere of radius $R_{e},$ the ratio of the magnitudes of their orbital velocities is :-

$\frac{R _{B}}{R _{A}}$

$\frac{R _{B} + R _{e}}{R _{A} + R _{e}}$

$\frac{R _{B} + R _{e}}{R _{A} + R _{e}}$

$(\frac{R _{A}}{R _{B}})^{2}$

since, orbital velocity is inversely proportional to the square root of the radius of the orbit,
$\frac{v _{A}}{v _{B}} = \frac{R _{B} + R _{e}}{R _{A} + R _{e}}$

Q. Two satellites A and B go around the earth in circular orbits at heights of RA​ and RB​ respectively from the surface of the earth. Assuming the earth to be a uniform sphere of radius Re​, the ratio of the magnitudes of their orbital velocities is :-

RA​RB​​​

RA​+Re​RB​+Re​​

RA​+Re​RB​+Re​​​

(RB​RA​​)2

since, orbital velocity is inversely proportional to the square root of the radius of the orbit, vB​vA​​=RA​+Re​RB​+Re​​​

Q. Two satellites $A$ and $B$ go around the earth in circular orbits at heights of $R_{A}$ and $R_{B}$ respectively from the surface of the earth. Assuming the earth to be a uniform sphere of radius $R_{e},$ the ratio of the magnitudes of their orbital velocities is :-

$\frac{R _{B}}{R _{A}}$

$\frac{R _{B} + R _{e}}{R _{A} + R _{e}}$

$\frac{R _{B} + R _{e}}{R _{A} + R _{e}}$

$(\frac{R _{A}}{R _{B}})^{2}$

since, orbital velocity is inversely proportional to the square root of the radius of the orbit,
$\frac{v _{A}}{v _{B}} = \frac{R _{B} + R _{e}}{R _{A} + R _{e}}$