Two resistors of resistances R1=(300 ±3) Ω and R2=(500 ±4) Ω are connected in series. The equivalent resistance of the series combination is

Question

Two resistors of resistances R1=(300 ±3) Ω and R2=(500 ±4) Ω are connected in series. The equivalent resistance of the series combination is (A) (800 ± 1) Ω  (B) (800 ± 7) Ω  (C) (200 ± 7) Ω  (D) (200 ± 1) Ω

Tardigrade Admin · Accepted Answer

The equivalent resistance of series combination is

R_{s} = R_{1} + R_{2} = 300 Ω + 500 Ω = 800 Ω

The error in equivalent resistance is given by

Δ R = (Δ R_{1} + Δ R_{2}) = (3 + 4) Ω = 7 Ω

Hence, the equivalent resistance along with error is

(800 \pm 7) Ω

.

Q. Two resistors of resistances $R_{1} = (300 \pm 3) Ω$ and $R_{2} = (500 \pm 4) Ω$ are connected in series. The equivalent resistance of the series combination is

$(800 \pm 1) Ω$

$(800 \pm 7) Ω$

$(200 \pm 7) Ω$

$(200 \pm 1) Ω$

The equivalent resistance of series combination is
$R_{s} = R_{1} + R_{2} = 300 Ω + 500 Ω = 800 Ω$
The error in equivalent resistance is given by
$Δ R = (Δ R_{1} + Δ R_{2}) = (3 + 4) Ω = 7 Ω$
Hence, the equivalent resistance along with error is $(800 \pm 7) Ω$ .

Q. Two resistors of resistances R1​=(300±3)Ω and R2​=(500±4)Ω are connected in series. The equivalent resistance of the series combination is

(800±1)Ω

(800±7)Ω

(200±7)Ω

(200±1)Ω