Q.
Two resistors of resistances R1=(100±3)Ω and R2=(200±4)Ω are connected in parallel. The equivalent resistance of the parallel combination is
3787
215
Physical World, Units and Measurements
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Solution:
Here, R1=(100±3)Ω; R2=(200±4)Ω
The equivalent resistance in parallel combination is Rp1=R11+R21,Rp1=1001+2001=2003, Rp=3200=66.7Ω
The error in equivalent resistance is given by Rp2ΔRp=R12ΔR1+R22ΔR2; ΔR1(R1Rp)2+ΔR2(R2Rp)2 =3(10066.7)2+4(20066.7)2=1.8Ω
Hence, the equivalent resistance along with error in parallel combination is (66.7±1.8)Ω.