Two resistor R1=(24±0.5)Ω and R2=(8±0.3)Ω are joined in series. The equivalent resistance is

Question

Two resistor R1=(24±0.5)Ω and R2=(8±0.3)Ω are joined in series. The equivalent resistance is (A) 32±0.33 Ω (B) 32±0.8 Ω (C) 32±0.2 Ω (D) 32±0.5 Ω

Tardigrade Admin · Accepted Answer

R1=(24±0.5)Ω R2=(8±0.3)Ω RS=R1+R2=(32±0.8)Ω

Q. Two resistor $R_{1} = (24 \pm 0.5) Ω$ and $R_{2} = (8 \pm 0.3) Ω$ are joined in series. The equivalent resistance is