Two resistance of 10 Ω and 20 Ω and an inductor of inductance 5 H are connected to a battery of 2 V through a key K as shown in the figure. At time t=0 when the key K is closed, the initial current through the battery is:

Question

Two resistance of 10 Ω and 20 Ω and an inductor of inductance 5 H are connected to a battery of 2 V through a key K as shown in the figure. At time t=0 when the key K is closed, the initial current through the battery is: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/cf66397d1c6264a7782fe248376387a4-.png" /> (A) 0.2 A (B) (2/15) A (C) (1/15) A (D) 0 A

Tardigrade Admin · Accepted Answer

Initially the inductance will oppose the current which tries to flow through the inductance. But 10 Ω and 20 Ω can conduct. The current will be According to ohm's law I=(V/R)=(1/30)=(1/15) A

Q. Two resistance of $10 Ω$ and $20 Ω$ and an inductor of inductance $5 H$ are connected to a battery of $2 V$ through a key $K$ as shown in the figure. At time $t = 0$ when the key $K$ is closed, the initial current through the battery is:

$0.2 A$

$\frac{2}{15} A$

$\frac{1}{15} A$

$0 A$

Initially the inductance will oppose the current which tries to flow through the inductance. But $10 Ω$ and $20 Ω$ can conduct. The current will be
According to ohm's law
$I = \frac{V}{R} = \frac{1}{30} = \frac{1}{15} A$

Q. Two resistance of 10Ω and 20Ω and an inductor of inductance 5H are connected to a battery of 2V through a key K as shown in the figure. At time t=0 when the key K is closed, the initial current through the battery is:

0.2A

152​A

151​A

0A