Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Two reactions are given below: C(graphite) + O2(g) → CO2(g); Δ H = - 393.7 kj ; C(diamond) → C(graphite); Δ H = -2.1 kj What quantity of diamond will give 800 kj of heat on burning?
Q. Two reactions are given below :
C
(
g
r
a
p
hi
t
e
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
393.7
kj
;
C
(
d
iam
o
n
d
)
→
C
(
g
r
a
p
hi
t
e
)
;
Δ
H
=
−
2.1
kj
What quantity of diamond will give
800
kj
of heat on burning?
3201
236
Thermodynamics
Report Error
A
24.25
g
35%
B
15.24
g
28%
C
2
g
23%
D
12.12
g
14%
Solution:
C
(
d
iam
o
n
d
)
→
O
2
(
g
)
→
C
O
2
(
g
)
=
−
393.7
+
(
−
2.1
)
=
−
395.8
kj
12
g
diamond gives
395.8
kj
.
800
kj
will be given by
395.8
12
×
800
=
24.25
g