Two poles standing on a horizontal ground are of heights 5 m and 10 m respectively. The line joining their tops makes an angle of 15° with ground. Then the distance (in m) between the poles, is :

Question

Two poles standing on a horizontal ground are of heights 5 m and 10 m respectively. The line joining their tops makes an angle of 15° with ground. Then the distance (in m) between the poles, is : (A) (5/2)(2+√3)  (B)  5( √3 + 1) (C)  5( 2 + √3 ) (D)  10 ( √3 - 1)

Tardigrade Admin · Accepted Answer

tan 15° = (5/x) 2 - √13 = (5/x) x=5 (2+√3)

Q. Two poles standing on a horizontal ground are of heights $5 m$ and $10 m$ respectively. The line joining their tops makes an angle of $1 5^{\circ}$ with ground. Then the distance (in m) between the poles, is :

$\frac{5}{2} (2 + 3)$

$5 (3 + 1)$

$5 (2 + 3)$

$10 (3 - 1)$

$tan 1 5^{\circ} = \frac{5}{x}$
$2 - 13 = \frac{5}{x}$
$x = 5 (2 + 3)$

Q. Two poles standing on a horizontal ground are of heights 5m and 10m respectively. The line joining their tops makes an angle of 15∘ with ground. Then the distance (in m) between the poles, is :

25​(2+3​)

5(3​+1)

5(2+3​)

10(3​−1)