Two poles are separated by a distance of 3.14 m. The resolving power of human eye is 1 minute of an arc. The maximum distance from which he can identify the two poles distinctly is

Question

Two poles are separated by a distance of 3.14 m. The resolving power of human eye is 1 minute of an arc. The maximum distance from which he can identify the two poles distinctly is (A) 10.8 km (B) 5.4 km (C) 188 m (D) 376 m

Tardigrade Admin · Accepted Answer

Given the lateral separation of the poles

d = 3.14 m

The resolving power of the eye is

θ = 1 min = π / (60 \times 180)

rad
The maximum distance from which poles are distinctly visible is

D = d / θ

\Rightarrow D = (3.14 \times 60 \times 180) / π

= 10800 m = 10.8 km

Q. Two poles are separated by a distance of 3.14m. The resolving power of human eye is 1 minute of an arc. The maximum distance from which he can identify the two poles distinctly is

10.8 km

5.4 km

188 m

376 m

Given the lateral separation of the poles d=3.14m The resolving power of the eye is θ=1min=π/(60×180) rad The maximum distance from which poles are distinctly visible is D=d/θ ⇒D=(3.14×60×180)/π =10800m=10.8km

Q. Two poles are separated by a distance of $3.14 m$ . The resolving power of human eye is $1$ minute of an arc. The maximum distance from which he can identify the two poles distinctly is

Given the lateral separation of the poles $d = 3.14 m$
The resolving power of the eye is
$θ = 1 min = π / (60 \times 180)$ rad
The maximum distance from which poles are distinctly visible is
$D = d / θ$
$\Rightarrow D = (3.14 \times 60 \times 180) / π$
$= 10800 m = 10.8 km$