Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points?

Question

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points? (A) π (B) (π/6) (C) (π/3) (D) (2 π/3)

Tardigrade Admin · Accepted Answer

As, Wavelength = Velocity of wave × time period i. e. λ=300 × 0.05 or λ=15 m According to the problem path difference between two points =15-10=5 m ∴ Phase difference =(2 π/λ) × path difference Δ φ =(2 π/λ) × Δ x =(2 π/15) × 5=(2 π/3)

Q. Two points are located at a distance of $10 m$ and $15 m$ from the source of oscillation. The period of oscillation is $0.05 s$ and the velocity of the wave is $300 m / s$ . What is the phase difference between the oscillations of two points?

$π$

$\frac{π}{6}$

$\frac{π}{3}$

$\frac{2 π}{3}$

Q. Two points are located at a distance of 10m and 15m from the source of oscillation. The period of oscillation is 0.05s and the velocity of the wave is 300m/s. What is the phase difference between the oscillations of two points?

π

6π​

3π​

32π​

As, Wavelength = Velocity of wave × time period i. e. λ=300×0.05 or λ=15m According to the problem path difference between two points =15−10=5m ∴ Phase difference =λ2π​× path difference Δϕ=λ2π​×Δx =152π​×5=32π​

Q. Two points are located at a distance of $10 m$ and $15 m$ from the source of oscillation. The period of oscillation is $0.05 s$ and the velocity of the wave is $300 m / s$ . What is the phase difference between the oscillations of two points?

$π$

$\frac{π}{6}$

$\frac{π}{3}$

$\frac{2 π}{3}$