Two point charges qA=3 μ C and qB=-3 μ C are located 20 cm apart in vacuum. If a negative test charge of magnitude 1.5 × 10-9 C is placed at this point, what is the force experienced by the test charge?

Question

Two point charges qA=3 μ C and qB=-3 μ C are located 20 cm apart in vacuum. If a negative test charge of magnitude 1.5 × 10-9 C is placed at this point, what is the force experienced by the test charge? (A) 7.2 × 10-3 N (B) 8.1 × 10-3 N (C) 9.0 × 10-3 N (D) 9.6 × 10-3 N

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/080c9f9c84b56d18f66e2d0dde6499bf-.png" /> EP=2[((9 × 109)(3 × 10-6)/0.12)]=5.4 × 106 N C -1 FP=EP prime qp=(5.4 × 106)(1.5 × 10-9) N =8.1 × 10-3 N

Q. Two point charges $q_{A} = 3 μ C$ and $q_{B} = - 3 μ C$ are located $20 c m$ apart in vacuum. If a negative test charge of magnitude $1.5 \times 1 0^{- 9} C$ is placed at this point, what is the force experienced by the test charge?

$7.2 \times 1 0^{- 3} N$

$8.1 \times 1 0^{- 3} N$

$9.0 \times 1 0^{- 3} N$

$9.6 \times 1 0^{- 3} N$

$E_{P} = 2 [\frac{( 9 \times 1 0 ^{9} ) ( 3 \times 1 0 ^{- 6} )}{0. 1 ^{2}}] = 5.4 \times 1 0^{6} N C^{- 1}$
$F_{P} = E_{P^{'}} q_{p} = (5.4 \times 1 0^{6}) (1.5 \times 1 0^{- 9}) N = 8.1 \times 1 0^{- 3} N$

Q. Two point charges qA​=3μC and qB​=−3μC are located 20cm apart in vacuum. If a negative test charge of magnitude 1.5×10−9C is placed at this point, what is the force experienced by the test charge?

7.2×10−3N

8.1×10−3N

9.0×10−3N

9.6×10−3N