Two plates are 2 cm apart. A potential difference of 10 volt is applied between them. The electric field between the plates is

Question

Two plates are 2 cm apart. A potential difference of 10 volt is applied between them. The electric field between the plates is (A) 20 N/C (B) 500 N/C (C) 5 N/C (D) 250 N/C

Tardigrade Admin · Accepted Answer

E=(V/d)=(10/2 × 10-2) =500 N / C

Q. Two plates are $2 c m$ apart. A potential difference of $10$ volt is applied between them. The electric field between the plates is

20 N/C

500 N/C

5 N/C

250 N/C

$E = \frac{V}{d} = \frac{10}{2 \times 1 0 ^{- 2}}$
$= 500 N / C$

Q. Two plates are 2cm apart. A potential difference of 10 volt is applied between them. The electric field between the plates is